For the equation to have positive and real roots, two extra conditions are ... Notice your equation is the same as x2+x(2−2m)+(3−m)=0 ... If the Δ of a quadrationequation iz 0, then you get unique solution. if Δ<0, .... Find all values for prime p, so that x2+px−330p=0only has one

hello :  calculate  delta b²-4ac a = m       b= m²-3m+2      c = 2m-6  .....m no zero