The system of equations is 2x -  3y -  2z  = 4                 (1)    x + 3y + 2z = -7                (2) -4x - 4y -  2z = 10               (3) There are many methods for solving the system of equations, including matrix methods. I shall use basic algebraic methods. Subtract (3) from (1). 6x + y = -6                   (4) Add (2) and (3). -3x - y = 3                     (5) Add (4) and (5). 3x = -3 x = -1 From (4), obtain y = -6 - 6x    = -6 +6    = 0 From (2), obtain 2z = -7 - x - 3y      = -7 + 1      = -6 z = -3 Answer: (-1, 0, -3) The solution is x = -1, y = 0, z = -3.