find three consecutive even integers such that the sum of the smallest integer and twice the median integer is 20more than the largest integer.

ANSWERS

2015-11-07 00:04:30

x = smallest; x + 2 = middle, and x + 4 = largest x + 2(x+2) = 20 + x + 4 x + 2x + 4=24 +x 3x + 4 = 24 + x 2x = 20 x = 10 so the three integers are 10, 12, and 14

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