The answer is -⅘ + ⅖i

[latex] cfrac{ sqrt{-4} }{(3+i)-(2+3i)} = cfrac{ 2i}{3+i-2-3i} = cfrac{ 2i}{1-2i}= cfrac{ 2i(1+2i)}{(1-2i)(1+2i)}= \\=cfrac{ 2i-4}{1+4}= cfrac{ -4+2i}{5}[/latex]