Chemistry
Jann157
2021-02-22 05:59:18
How many moles of hexane (C6H14) must burn to form 18.4 mol of carbon dioxide?
ANSWERS
Ducckyluver143
2021-02-22 07:05:14

The combustion reaction of hexane: 2 C6H14 + 19 O2 = 12 CO2 + 14 H2O 2 mol C6H14 ---------> 12 mol CO2 x mol C6H14 ---------> 18.4 mol CO2 12 * x = 18.4 * 2 12 x = 36.8 x = 36.8 / 12 x = 3.067 moles of CO2 hope this helps!.

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